Hi,
Another day, in another forum, regarding the formula:
C(n,k,t,m)=b
I was thinking that for m=t, the ideal wheeling system would be:
b >= Comb(n,t) / Comb(k,t)
For instance: if we have a lotto 6/49, and we pick 10 numbers, and we wish to have a 4 if we have 4 numbers right, then:
b >= Comb(10,4) / Comb(6,4) = 210 / 15 = 14
But what if we want to guarantee 3 if we have 5 right in 10, for instance? How do we introduce the m variable, different from t?
Kind regards,
Kepler
Ideal" wheel system
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